Resuelve la integral

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✎ Solución paso a paso

1. 1
   $$÷x^2:=\int \frac{1+\frac{1}{x^2}}{x^2+\frac{1}{x^2}}dx$$
2. 2
   $$u=x-\frac{1}{x}\Rightarrow du=(1+\frac{1}{x^2})dx,x^2+\frac{1}{x^2}=u^2+2$$

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